9(z+4)-4(z-2)=2(z-2)+2(z-1)

Solution for 9(z+4)-4(z-2)=2(z-2)+2(z-1) equation:

9(z+4)-4(z-2)=2(z-2)+2(z-1)

We move all terms to the left:

9(z+4)-4(z-2)-(2(z-2)+2(z-1))=0

We multiply parentheses

9z-4z-(2(z-2)+2(z-1))+36+8=0


We calculate terms in parentheses: -(2(z-2)+2(z-1)), so:

2(z-2)+2(z-1)

We multiply parentheses

2z+2z-4-2

We add all the numbers together, and all the variables

4z-6

Back to the equation:

-(4z-6)


We add all the numbers together, and all the variables

5z-(4z-6)+44=0

We get rid of parentheses

5z-4z+6+44=0

We add all the numbers together, and all the variables

z+50=0

We move all terms containing z to the left, all other terms to the right

z=-50