9(z+1)=8(z-2)+z

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Solution for 9(z+1)=8(z-2)+z equation:


Simplifying
9(z + 1) = 8(z + -2) + z

Reorder the terms:
9(1 + z) = 8(z + -2) + z
(1 * 9 + z * 9) = 8(z + -2) + z
(9 + 9z) = 8(z + -2) + z

Reorder the terms:
9 + 9z = 8(-2 + z) + z
9 + 9z = (-2 * 8 + z * 8) + z
9 + 9z = (-16 + 8z) + z

Combine like terms: 8z + z = 9z
9 + 9z = -16 + 9z

Add '-9z' to each side of the equation.
9 + 9z + -9z = -16 + 9z + -9z

Combine like terms: 9z + -9z = 0
9 + 0 = -16 + 9z + -9z
9 = -16 + 9z + -9z

Combine like terms: 9z + -9z = 0
9 = -16 + 0
9 = -16

Solving
9 = -16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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