9(z+1)-2(z-2)=4(z-1)+2(z-1)

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Solution for 9(z+1)-2(z-2)=4(z-1)+2(z-1) equation:


9(z+1)-2(z-2)=4(z-1)+2(z-1)

We simplify the equation to the form, which is simple to understand
9(z+1)-2(z-2)=4(z-1)+2(z-1)

Reorder the terms in parentheses
+(+9z+9)-2*(z-2)=4*(z-1)+2*(z-1)

Remove unnecessary parentheses
+9z+9-2+*(+z-2+)=+4+*(+z-1+)+2+*(+z-1+)

Reorder the terms in parentheses
+9z+9+(-2z+4)=4*(z-1)+2*(z-1)

Remove unnecessary parentheses
+9z+9-2z+4=+4+*(+z-1+)+2+*(+z-1+)

Reorder the terms in parentheses
+9z+9-2z+4=+(+4z-4)+2*(z-1)

Remove unnecessary parentheses
+9z+9-2z+4=+4z-4+2+*(+z-1+)

Reorder the terms in parentheses
+9z+9-2z+4=+4z-4+(+2z-2)

Remove unnecessary parentheses
+9z+9-2z+4=+4z-4+2z-2

We move all terms containing z to the left and all other terms to the right.
+9z-2z-4z-2z=-4-2-9-4

We simplify left and right side of the equation.
+1z=-19

We divide both sides of the equation by 1 to get z.
z=-19

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