9(y-4)=-10(y+2(1/3

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Solution for 9(y-4)=-10(y+2(1/3 equation: 



9(y-4)=-10(y+2(1/3

We move all terms to the left:

9(y-4)-(-10(y+2(1/3)=0

We add all the numbers together, and all the variables

9(y-4)-(-10(y+2(+1/3)=0

We multiply parentheses

9y-(-10(y+2(+1/3)-36=0

We multiply all the terms by the denominator


9y*3)-36-(-10(y+2(+1=0

Wy multiply elements

27y^2-10(y+2(+1=0

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