9(y+-4)+-7=5(3y+-2)

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Solution for 9(y+-4)+-7=5(3y+-2) equation: 



9(y+-4)+-7=5(3y+-2)

We move all terms to the left:

9(y+-4)+-7-(5(3y+-2))=0

We add all the numbers together, and all the variables

9(y-4)-(5(3y-2))-7+=0

We add all the numbers together, and all the variables

9(y-4)-(5(3y-2))=0

We multiply parentheses

9y-(5(3y-2))-36=0



We calculate terms in parentheses: -(5(3y-2)), so:

5(3y-2)

We multiply parentheses

15y-10

Back to the equation:

-(15y-10)



We get rid of parentheses

9y-15y+10-36=0

We add all the numbers together, and all the variables

-6y-26=0

We move all terms containing y to the left, all other terms to the right

-6y=26

y=26/-6

y=-4+1/3

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