9(x2+4)=6(x+2)

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Solution for 9(x2+4)=6(x+2) equation: 



9(x2+4)=6(x+2)

We move all terms to the left:

9(x2+4)-(6(x+2))=0

We add all the numbers together, and all the variables

9(+x^2+4)-(6(x+2))=0

We multiply parentheses

9x^2-(6(x+2))+36=0



We calculate terms in parentheses: -(6(x+2)), so:

6(x+2)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

9x^2-6x-12+36=0

We add all the numbers together, and all the variables

9x^2-6x+24=0

a = 9; b = -6; c = +24;
Δ = b2-4ac
Δ = -62-4·9·24
Δ = -828
Delta is less than zero, so there is no solution for the equation

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