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9(x-5)=8-(x+5)
We move all terms to the left:
9(x-5)-(8-(x+5))=0
We multiply parentheses
9x-(8-(x+5))-45=0
We calculate terms in parentheses: -(8-(x+5)), so:We get rid of parentheses
8-(x+5)
determiningTheFunctionDomain -(x+5)+8
We get rid of parentheses
-x-5+8
We add all the numbers together, and all the variables
-1x+3
Back to the equation:
-(-1x+3)
9x+1x-3-45=0
We add all the numbers together, and all the variables
10x-48=0
We move all terms containing x to the left, all other terms to the right
10x=48
x=48/10
x=4+4/5
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