9(x-5)=27(6x-10)

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Solution for 9(x-5)=27(6x-10) equation: 



9(x-5)=27(6x-10)

We move all terms to the left:

9(x-5)-(27(6x-10))=0

We multiply parentheses

9x-(27(6x-10))-45=0



We calculate terms in parentheses: -(27(6x-10)), so:

27(6x-10)

We multiply parentheses

162x-270

Back to the equation:

-(162x-270)



We get rid of parentheses

9x-162x+270-45=0

We add all the numbers together, and all the variables

-153x+225=0

We move all terms containing x to the left, all other terms to the right

-153x=-225

x=-225/-153

x=1+8/17

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