9(x-4)-7(x+6)=2(x-5)+x

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Solution for 9(x-4)-7(x+6)=2(x-5)+x equation: 



9(x-4)-7(x+6)=2(x-5)+x

We move all terms to the left:

9(x-4)-7(x+6)-(2(x-5)+x)=0

We multiply parentheses

9x-7x-(2(x-5)+x)-36-42=0



We calculate terms in parentheses: -(2(x-5)+x), so:

2(x-5)+x

We add all the numbers together, and all the variables

x+2(x-5)

We multiply parentheses

x+2x-10

We add all the numbers together, and all the variables

3x-10

Back to the equation:

-(3x-10)



We add all the numbers together, and all the variables

2x-(3x-10)-78=0

We get rid of parentheses

2x-3x+10-78=0

We add all the numbers together, and all the variables

-1x-68=0

We move all terms containing x to the left, all other terms to the right

-x=68

x=68/-1

x=-68

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