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9(x-3)-3(x-7)=4x+3+x-2
We move all terms to the left:
9(x-3)-3(x-7)-(4x+3+x-2)=0
We add all the numbers together, and all the variables
9(x-3)-3(x-7)-(5x+1)=0
We multiply parentheses
9x-3x-(5x+1)-27+21=0
We get rid of parentheses
9x-3x-5x-1-27+21=0
We add all the numbers together, and all the variables
x-7=0
We move all terms containing x to the left, all other terms to the right
x=7
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