9(x-1)/3=3x(x+8)/10

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Solution for 9(x-1)/3=3x(x+8)/10 equation: 



9(x-1)/3=3x(x+8)/10

We move all terms to the left:

9(x-1)/3-(3x(x+8)/10)=0

We calculate fractions


9x/()+(-(3x(x+8)*3)/()=0



We calculate terms in parentheses: +(-(3x(x+8)*3)/(), so:

-(3x(x+8)*3)/(

We multiply all the terms by the denominator


-(3x(x+8)*3)



We calculate terms in parentheses: -(3x(x+8)*3), so:

3x(x+8)*3

We multiply parentheses

9x^2+72x

Back to the equation:

-(9x^2+72x)



We get rid of parentheses

-9x^2-72x

Back to the equation:

+(-9x^2-72x)



We get rid of parentheses

-9x^2-72x+9x/()=0

We multiply all the terms by the denominator


-9x^2*()-72x*()+9x=0

We add all the numbers together, and all the variables

-9x^2*()+9x-72x*()=0

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