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9(x+8)+x=3(x+2)-8
We move all terms to the left:
9(x+8)+x-(3(x+2)-8)=0
We add all the numbers together, and all the variables
x+9(x+8)-(3(x+2)-8)=0
We multiply parentheses
x+9x-(3(x+2)-8)+72=0
We calculate terms in parentheses: -(3(x+2)-8), so:We add all the numbers together, and all the variables
3(x+2)-8
We multiply parentheses
3x+6-8
We add all the numbers together, and all the variables
3x-2
Back to the equation:
-(3x-2)
10x-(3x-2)+72=0
We get rid of parentheses
10x-3x+2+72=0
We add all the numbers together, and all the variables
7x+74=0
We move all terms containing x to the left, all other terms to the right
7x=-74
x=-74/7
x=-10+4/7
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