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9(x+3)=2(x+2)
We move all terms to the left:
9(x+3)-(2(x+2))=0
We multiply parentheses
9x-(2(x+2))+27=0
We calculate terms in parentheses: -(2(x+2)), so:We get rid of parentheses
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
9x-2x-4+27=0
We add all the numbers together, and all the variables
7x+23=0
We move all terms containing x to the left, all other terms to the right
7x=-23
x=-23/7
x=-3+2/7
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