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9(x+3)-9=3x+6(3+x)
We move all terms to the left:
9(x+3)-9-(3x+6(3+x))=0
We add all the numbers together, and all the variables
9(x+3)-(3x+6(x+3))-9=0
We multiply parentheses
9x-(3x+6(x+3))+27-9=0
We calculate terms in parentheses: -(3x+6(x+3)), so:We add all the numbers together, and all the variables
3x+6(x+3)
We multiply parentheses
3x+6x+18
We add all the numbers together, and all the variables
9x+18
Back to the equation:
-(9x+18)
9x-(9x+18)+18=0
We get rid of parentheses
9x-9x-18+18=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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