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9(x+1)-7=3(2x+9)
We move all terms to the left:
9(x+1)-7-(3(2x+9))=0
We multiply parentheses
9x-(3(2x+9))+9-7=0
We calculate terms in parentheses: -(3(2x+9)), so:We add all the numbers together, and all the variables
3(2x+9)
We multiply parentheses
6x+27
Back to the equation:
-(6x+27)
9x-(6x+27)+2=0
We get rid of parentheses
9x-6x-27+2=0
We add all the numbers together, and all the variables
3x-25=0
We move all terms containing x to the left, all other terms to the right
3x=25
x=25/3
x=8+1/3
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