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9(x+1)+1=6x+3(3+x)
We move all terms to the left:
9(x+1)+1-(6x+3(3+x))=0
We add all the numbers together, and all the variables
9(x+1)-(6x+3(x+3))+1=0
We multiply parentheses
9x-(6x+3(x+3))+9+1=0
We calculate terms in parentheses: -(6x+3(x+3)), so:We add all the numbers together, and all the variables
6x+3(x+3)
We multiply parentheses
6x+3x+9
We add all the numbers together, and all the variables
9x+9
Back to the equation:
-(9x+9)
9x-(9x+9)+10=0
We get rid of parentheses
9x-9x-9+10=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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