9(u+3)=3u+9

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Solution for 9(u+3)=3u+9 equation: 



9(u+3)=3u+9

We move all terms to the left:

9(u+3)-(3u+9)=0

We multiply parentheses

9u-(3u+9)+27=0

We get rid of parentheses

9u-3u-9+27=0

We add all the numbers together, and all the variables

6u+18=0

We move all terms containing u to the left, all other terms to the right

6u=-18

u=-18/6

u=-3

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