9(t-4)-21=5(t-2)

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Solution for 9(t-4)-21=5(t-2) equation: 



9(t-4)-21=5(t-2)

We move all terms to the left:

9(t-4)-21-(5(t-2))=0

We multiply parentheses

9t-(5(t-2))-36-21=0



We calculate terms in parentheses: -(5(t-2)), so:

5(t-2)

We multiply parentheses

5t-10

Back to the equation:

-(5t-10)



We add all the numbers together, and all the variables

9t-(5t-10)-57=0

We get rid of parentheses

9t-5t+10-57=0

We add all the numbers together, and all the variables

4t-47=0

We move all terms containing t to the left, all other terms to the right

4t=47

t=47/4

t=11+3/4

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