9(q+2)=3(q-12)

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Solution for 9(q+2)=3(q-12) equation: 



9(q+2)=3(q-12)

We move all terms to the left:

9(q+2)-(3(q-12))=0

We multiply parentheses

9q-(3(q-12))+18=0



We calculate terms in parentheses: -(3(q-12)), so:

3(q-12)

We multiply parentheses

3q-36

Back to the equation:

-(3q-36)



We get rid of parentheses

9q-3q+36+18=0

We add all the numbers together, and all the variables

6q+54=0

We move all terms containing q to the left, all other terms to the right

6q=-54

q=-54/6

q=-9

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