9(n-4)-7=32-2(n+3)

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Solution for 9(n-4)-7=32-2(n+3) equation: 



9(n-4)-7=32-2(n+3)

We move all terms to the left:

9(n-4)-7-(32-2(n+3))=0

We multiply parentheses

9n-(32-2(n+3))-36-7=0



We calculate terms in parentheses: -(32-2(n+3)), so:

32-2(n+3)

determiningTheFunctionDomain
-2(n+3)+32

We multiply parentheses

-2n-6+32

We add all the numbers together, and all the variables

-2n+26

Back to the equation:

-(-2n+26)



We add all the numbers together, and all the variables

9n-(-2n+26)-43=0

We get rid of parentheses

9n+2n-26-43=0

We add all the numbers together, and all the variables

11n-69=0

We move all terms containing n to the left, all other terms to the right

11n=69

n=69/11

n=6+3/11

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