9(n+3)-10(n-5)=27

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Solution for 9(n+3)-10(n-5)=27 equation: 



9(n+3)-10(n-5)=27

We move all terms to the left:

9(n+3)-10(n-5)-(27)=0

We multiply parentheses

9n-10n+27+50-27=0

We add all the numbers together, and all the variables

-1n+50=0

We move all terms containing n to the left, all other terms to the right

-n=-50

n=-50/-1

n=+50

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