9(m-8)=7(2m+1)=3

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Solution for 9(m-8)=7(2m+1)=3 equation: 



9(m-8)=7(2m+1)=3

We move all terms to the left:

9(m-8)-(7(2m+1))=0

We multiply parentheses

9m-(7(2m+1))-72=0



We calculate terms in parentheses: -(7(2m+1)), so:

7(2m+1)

We multiply parentheses

14m+7

Back to the equation:

-(14m+7)



We get rid of parentheses

9m-14m-7-72=0

We add all the numbers together, and all the variables

-5m-79=0

We move all terms containing m to the left, all other terms to the right

-5m=79

m=79/-5

m=-15+4/5

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