9(m+1)=3(2m+5)

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Solution for 9(m+1)=3(2m+5) equation: 



9(m+1)=3(2m+5)

We move all terms to the left:

9(m+1)-(3(2m+5))=0

We multiply parentheses

9m-(3(2m+5))+9=0



We calculate terms in parentheses: -(3(2m+5)), so:

3(2m+5)

We multiply parentheses

6m+15

Back to the equation:

-(6m+15)



We get rid of parentheses

9m-6m-15+9=0

We add all the numbers together, and all the variables

3m-6=0

We move all terms containing m to the left, all other terms to the right

3m=6

m=6/3

m=2

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