9(k-4)-7k=32-2(k+2)

Solution for 9(k-4)-7k=32-2(k+2) equation:

9(k-4)-7k=32-2(k+2)

We move all terms to the left:

9(k-4)-7k-(32-2(k+2))=0

We add all the numbers together, and all the variables

-7k+9(k-4)-(32-2(k+2))=0

We multiply parentheses

-7k+9k-(32-2(k+2))-36=0


We calculate terms in parentheses: -(32-2(k+2)), so:

32-2(k+2)

determiningTheFunctionDomain
-2(k+2)+32

We multiply parentheses

-2k-4+32

We add all the numbers together, and all the variables

-2k+28

Back to the equation:

-(-2k+28)


We add all the numbers together, and all the variables

2k-(-2k+28)-36=0

We get rid of parentheses

2k+2k-28-36=0

We add all the numbers together, and all the variables

4k-64=0

We move all terms containing k to the left, all other terms to the right

4k=64

k=64/4

k=16