9(k-3)=4(k-2)

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Solution for 9(k-3)=4(k-2) equation: 



9(k-3)=4(k-2)

We move all terms to the left:

9(k-3)-(4(k-2))=0

We multiply parentheses

9k-(4(k-2))-27=0



We calculate terms in parentheses: -(4(k-2)), so:

4(k-2)

We multiply parentheses

4k-8

Back to the equation:

-(4k-8)



We get rid of parentheses

9k-4k+8-27=0

We add all the numbers together, and all the variables

5k-19=0

We move all terms containing k to the left, all other terms to the right

5k=19

k=19/5

k=3+4/5

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