9(k-3)-7k=32-2(k+8)

Solution for 9(k-3)-7k=32-2(k+8) equation:

9(k-3)-7k=32-2(k+8)

We move all terms to the left:

9(k-3)-7k-(32-2(k+8))=0

We add all the numbers together, and all the variables

-7k+9(k-3)-(32-2(k+8))=0

We multiply parentheses

-7k+9k-(32-2(k+8))-27=0


We calculate terms in parentheses: -(32-2(k+8)), so:

32-2(k+8)

determiningTheFunctionDomain
-2(k+8)+32

We multiply parentheses

-2k-16+32

We add all the numbers together, and all the variables

-2k+16

Back to the equation:

-(-2k+16)


We add all the numbers together, and all the variables

2k-(-2k+16)-27=0

We get rid of parentheses

2k+2k-16-27=0

We add all the numbers together, and all the variables

4k-43=0

We move all terms containing k to the left, all other terms to the right

4k=43

k=43/4

k=10+3/4