9(k-2)=4(k+3)

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Solution for 9(k-2)=4(k+3) equation: 



9(k-2)=4(k+3)

We move all terms to the left:

9(k-2)-(4(k+3))=0

We multiply parentheses

9k-(4(k+3))-18=0



We calculate terms in parentheses: -(4(k+3)), so:

4(k+3)

We multiply parentheses

4k+12

Back to the equation:

-(4k+12)



We get rid of parentheses

9k-4k-12-18=0

We add all the numbers together, and all the variables

5k-30=0

We move all terms containing k to the left, all other terms to the right

5k=30

k=30/5

k=6

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