9(k+3)+23=4k

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Solution for 9(k+3)+23=4k equation: 



9(k+3)+23=4k

We move all terms to the left:

9(k+3)+23-(4k)=0

We add all the numbers together, and all the variables

-4k+9(k+3)+23=0

We multiply parentheses

-4k+9k+27+23=0

We add all the numbers together, and all the variables

5k+50=0

We move all terms containing k to the left, all other terms to the right

5k=-50

k=-50/5

k=-10

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