9(h+3)=3(h-2)

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Solution for 9(h+3)=3(h-2) equation: 



9(h+3)=3(h-2)

We move all terms to the left:

9(h+3)-(3(h-2))=0

We multiply parentheses

9h-(3(h-2))+27=0



We calculate terms in parentheses: -(3(h-2)), so:

3(h-2)

We multiply parentheses

3h-6

Back to the equation:

-(3h-6)



We get rid of parentheses

9h-3h+6+27=0

We add all the numbers together, and all the variables

6h+33=0

We move all terms containing h to the left, all other terms to the right

6h=-33

h=-33/6

h=-5+1/2

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