9(d-1)+1=4(2d+2)+2

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Solution for 9(d-1)+1=4(2d+2)+2 equation: 



9(d-1)+1=4(2d+2)+2

We move all terms to the left:

9(d-1)+1-(4(2d+2)+2)=0

We multiply parentheses

9d-(4(2d+2)+2)-9+1=0



We calculate terms in parentheses: -(4(2d+2)+2), so:

4(2d+2)+2

We multiply parentheses

8d+8+2

We add all the numbers together, and all the variables

8d+10

Back to the equation:

-(8d+10)



We add all the numbers together, and all the variables

9d-(8d+10)-8=0

We get rid of parentheses

9d-8d-10-8=0

We add all the numbers together, and all the variables

d-18=0

We move all terms containing d to the left, all other terms to the right

d=18

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