9(d+4)=4(d-7)-5

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Solution for 9(d+4)=4(d-7)-5 equation: 



9(d+4)=4(d-7)-5

We move all terms to the left:

9(d+4)-(4(d-7)-5)=0

We multiply parentheses

9d-(4(d-7)-5)+36=0



We calculate terms in parentheses: -(4(d-7)-5), so:

4(d-7)-5

We multiply parentheses

4d-28-5

We add all the numbers together, and all the variables

4d-33

Back to the equation:

-(4d-33)



We get rid of parentheses

9d-4d+33+36=0

We add all the numbers together, and all the variables

5d+69=0

We move all terms containing d to the left, all other terms to the right

5d=-69

d=-69/5

d=-13+4/5

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