9(d+2)=3(d-1)

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Solution for 9(d+2)=3(d-1) equation: 



9(d+2)=3(d-1)

We move all terms to the left:

9(d+2)-(3(d-1))=0

We multiply parentheses

9d-(3(d-1))+18=0



We calculate terms in parentheses: -(3(d-1)), so:

3(d-1)

We multiply parentheses

3d-3

Back to the equation:

-(3d-3)



We get rid of parentheses

9d-3d+3+18=0

We add all the numbers together, and all the variables

6d+21=0

We move all terms containing d to the left, all other terms to the right

6d=-21

d=-21/6

d=-3+1/2

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