9(c-4)+4=3+c-35

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Solution for 9(c-4)+4=3+c-35 equation: 



9(c-4)+4=3+c-35

We move all terms to the left:

9(c-4)+4-(3+c-35)=0

We add all the numbers together, and all the variables

9(c-4)-(c-32)+4=0

We multiply parentheses

9c-(c-32)-36+4=0

We get rid of parentheses

9c-c+32-36+4=0

We add all the numbers together, and all the variables

8c=0

c=0/8

c=0

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