9(c-3)+6=2+c-23

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Solution for 9(c-3)+6=2+c-23 equation:


Simplifying
9(c + -3) + 6 = 2 + c + -23

Reorder the terms:
9(-3 + c) + 6 = 2 + c + -23
(-3 * 9 + c * 9) + 6 = 2 + c + -23
(-27 + 9c) + 6 = 2 + c + -23

Reorder the terms:
-27 + 6 + 9c = 2 + c + -23

Combine like terms: -27 + 6 = -21
-21 + 9c = 2 + c + -23

Reorder the terms:
-21 + 9c = 2 + -23 + c

Combine like terms: 2 + -23 = -21
-21 + 9c = -21 + c

Add '21' to each side of the equation.
-21 + 21 + 9c = -21 + 21 + c

Combine like terms: -21 + 21 = 0
0 + 9c = -21 + 21 + c
9c = -21 + 21 + c

Combine like terms: -21 + 21 = 0
9c = 0 + c
9c = c

Solving
9c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
9c + -1c = c + -1c

Combine like terms: 9c + -1c = 8c
8c = c + -1c

Combine like terms: c + -1c = 0
8c = 0

Divide each side by '8'.
c = 0

Simplifying
c = 0

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