9(b-4)-7b=1/3(3b-2)

Solution for 9(b-4)-7b=1/3(3b-2) equation:

9(b-4)-7b=1/3(3b-2)

We move all terms to the left:

9(b-4)-7b-(1/3(3b-2))=0


Domain of the equation: 3(3b-2))!=0

b∈R


We add all the numbers together, and all the variables

-7b+9(b-4)-(1/3(3b-2))=0

We multiply parentheses

-7b+9b-(1/3(3b-2))-36=0

We multiply all the terms by the denominator


-7b*3(3b-2))+9b*3(3b-2))-(1-36*3(3b-2))=0

We add all the numbers together, and all the variables

-7b*3(3b-2))+9b*3(3b-2))-(1-36*3(3b=0

Wy multiply elements

-63b^3(3-2))-(1-36*3(3b=0

We do not support ebpression: b^3(3