9(b-4)-76=(3b-2)

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Solution for 9(b-4)-76=(3b-2) equation: 



9(b-4)-76=(3b-2)

We move all terms to the left:

9(b-4)-76-((3b-2))=0

We multiply parentheses

9b-((3b-2))-36-76=0



We calculate terms in parentheses: -((3b-2)), so:

(3b-2)

We get rid of parentheses

3b-2

Back to the equation:

-(3b-2)



We add all the numbers together, and all the variables

9b-(3b-2)-112=0

We get rid of parentheses

9b-3b+2-112=0

We add all the numbers together, and all the variables

6b-110=0

We move all terms containing b to the left, all other terms to the right

6b=110

b=110/6

b=18+1/3

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