9(b-1)-c+3b+c=

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Solution for 9(b-1)-c+3b+c= equation:


Simplifying
9(b + -1) + -1c + 3b + c = 0

Reorder the terms:
9(-1 + b) + -1c + 3b + c = 0
(-1 * 9 + b * 9) + -1c + 3b + c = 0
(-9 + 9b) + -1c + 3b + c = 0

Reorder the terms:
-9 + 9b + 3b + -1c + c = 0

Combine like terms: 9b + 3b = 12b
-9 + 12b + -1c + c = 0

Combine like terms: -1c + c = 0
-9 + 12b + 0 = 0
-9 + 12b = 0

Solving
-9 + 12b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 12b = 0 + 9

Combine like terms: -9 + 9 = 0
0 + 12b = 0 + 9
12b = 0 + 9

Combine like terms: 0 + 9 = 9
12b = 9

Divide each side by '12'.
b = 0.75

Simplifying
b = 0.75

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