9(b+5)+11=6b-10

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Solution for 9(b+5)+11=6b-10 equation:



9(b+5)+11=6b-10
We move all terms to the left:
9(b+5)+11-(6b-10)=0
We multiply parentheses
9b-(6b-10)+45+11=0
We get rid of parentheses
9b-6b+10+45+11=0
We add all the numbers together, and all the variables
3b+66=0
We move all terms containing b to the left, all other terms to the right
3b=-66
b=-66/3
b=-22

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