9(8d-5)+23=12d-3

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Solution for 9(8d-5)+23=12d-3 equation: 



9(8d-5)+23=12d-3

We move all terms to the left:

9(8d-5)+23-(12d-3)=0

We multiply parentheses

72d-(12d-3)-45+23=0

We get rid of parentheses

72d-12d+3-45+23=0

We add all the numbers together, and all the variables

60d-19=0

We move all terms containing d to the left, all other terms to the right

60d=19

d=19/60

d=19/60

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