9(4x-3)=3(6-2x)

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Solution for 9(4x-3)=3(6-2x) equation: 



9(4x-3)=3(6-2x)

We move all terms to the left:

9(4x-3)-(3(6-2x))=0

We add all the numbers together, and all the variables

9(4x-3)-(3(-2x+6))=0

We multiply parentheses

36x-(3(-2x+6))-27=0



We calculate terms in parentheses: -(3(-2x+6)), so:

3(-2x+6)

We multiply parentheses

-6x+18

Back to the equation:

-(-6x+18)



We get rid of parentheses

36x+6x-18-27=0

We add all the numbers together, and all the variables

42x-45=0

We move all terms containing x to the left, all other terms to the right

42x=45

x=45/42

x=1+1/14

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