9(3x-1)-8x=2(7x+5)-19

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Solution for 9(3x-1)-8x=2(7x+5)-19 equation: 



9(3x-1)-8x=2(7x+5)-19

We move all terms to the left:

9(3x-1)-8x-(2(7x+5)-19)=0

We add all the numbers together, and all the variables

-8x+9(3x-1)-(2(7x+5)-19)=0

We multiply parentheses

-8x+27x-(2(7x+5)-19)-9=0



We calculate terms in parentheses: -(2(7x+5)-19), so:

2(7x+5)-19

We multiply parentheses

14x+10-19

We add all the numbers together, and all the variables

14x-9

Back to the equation:

-(14x-9)



We add all the numbers together, and all the variables

19x-(14x-9)-9=0

We get rid of parentheses

19x-14x+9-9=0

We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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