9(3x+2)=33(12+x)

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Solution for 9(3x+2)=33(12+x) equation: 



9(3x+2)=33(12+x)

We move all terms to the left:

9(3x+2)-(33(12+x))=0

We add all the numbers together, and all the variables

9(3x+2)-(33(x+12))=0

We multiply parentheses

27x-(33(x+12))+18=0



We calculate terms in parentheses: -(33(x+12)), so:

33(x+12)

We multiply parentheses

33x+396

Back to the equation:

-(33x+396)



We get rid of parentheses

27x-33x-396+18=0

We add all the numbers together, and all the variables

-6x-378=0

We move all terms containing x to the left, all other terms to the right

-6x=378

x=378/-6

x=-63

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