9(3x+1)=11(x-3)

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Solution for 9(3x+1)=11(x-3) equation: 



9(3x+1)=11(x-3)

We move all terms to the left:

9(3x+1)-(11(x-3))=0

We multiply parentheses

27x-(11(x-3))+9=0



We calculate terms in parentheses: -(11(x-3)), so:

11(x-3)

We multiply parentheses

11x-33

Back to the equation:

-(11x-33)



We get rid of parentheses

27x-11x+33+9=0

We add all the numbers together, and all the variables

16x+42=0

We move all terms containing x to the left, all other terms to the right

16x=-42

x=-42/16

x=-2+5/8

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