9(3n-5)=(6n+4)+5

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Solution for 9(3n-5)=(6n+4)+5 equation: 



9(3n-5)=(6n+4)+5

We move all terms to the left:

9(3n-5)-((6n+4)+5)=0

We multiply parentheses

27n-((6n+4)+5)-45=0



We calculate terms in parentheses: -((6n+4)+5), so:

(6n+4)+5

We get rid of parentheses

6n+4+5

We add all the numbers together, and all the variables

6n+9

Back to the equation:

-(6n+9)



We get rid of parentheses

27n-6n-9-45=0

We add all the numbers together, and all the variables

21n-54=0

We move all terms containing n to the left, all other terms to the right

21n=54

n=54/21

n=2+4/7

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