9(3b-2)=2(b+16)

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Solution for 9(3b-2)=2(b+16) equation: 



9(3b-2)=2(b+16)

We move all terms to the left:

9(3b-2)-(2(b+16))=0

We multiply parentheses

27b-(2(b+16))-18=0



We calculate terms in parentheses: -(2(b+16)), so:

2(b+16)

We multiply parentheses

2b+32

Back to the equation:

-(2b+32)



We get rid of parentheses

27b-2b-32-18=0

We add all the numbers together, and all the variables

25b-50=0

We move all terms containing b to the left, all other terms to the right

25b=50

b=50/25

b=2

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