9(3a-4)=30-4(a+2)+7(2a-1)

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Solution for 9(3a-4)=30-4(a+2)+7(2a-1) equation: 



9(3a-4)=30-4(a+2)+7(2a-1)

We move all terms to the left:

9(3a-4)-(30-4(a+2)+7(2a-1))=0

We multiply parentheses

27a-(30-4(a+2)+7(2a-1))-36=0



We calculate terms in parentheses: -(30-4(a+2)+7(2a-1)), so:

30-4(a+2)+7(2a-1)

determiningTheFunctionDomain
-4(a+2)+7(2a-1)+30

We multiply parentheses

-4a+14a-8-7+30

We add all the numbers together, and all the variables

10a+15

Back to the equation:

-(10a+15)



We get rid of parentheses

27a-10a-15-36=0

We add all the numbers together, and all the variables

17a-51=0

We move all terms containing a to the left, all other terms to the right

17a=51

a=51/17

a=3

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