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9(3-x)=7(x+4)
We move all terms to the left:
9(3-x)-(7(x+4))=0
We add all the numbers together, and all the variables
9(-1x+3)-(7(x+4))=0
We multiply parentheses
-9x-(7(x+4))+27=0
We calculate terms in parentheses: -(7(x+4)), so:We get rid of parentheses
7(x+4)
We multiply parentheses
7x+28
Back to the equation:
-(7x+28)
-9x-7x-28+27=0
We add all the numbers together, and all the variables
-16x-1=0
We move all terms containing x to the left, all other terms to the right
-16x=1
x=1/-16
x=-1/16
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