9(3+y)=8(y-2)

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Solution for 9(3+y)=8(y-2) equation: 



9(3+y)=8(y-2)

We move all terms to the left:

9(3+y)-(8(y-2))=0

We add all the numbers together, and all the variables

9(y+3)-(8(y-2))=0

We multiply parentheses

9y-(8(y-2))+27=0



We calculate terms in parentheses: -(8(y-2)), so:

8(y-2)

We multiply parentheses

8y-16

Back to the equation:

-(8y-16)



We get rid of parentheses

9y-8y+16+27=0

We add all the numbers together, and all the variables

y+43=0

We move all terms containing y to the left, all other terms to the right

y=-43

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