9(3+b)=4(b+23)

Solution for 9(3+b)=4(b+23) equation:

9(3+b)=4(b+23)

We move all terms to the left:

9(3+b)-(4(b+23))=0

We add all the numbers together, and all the variables

9(b+3)-(4(b+23))=0

We multiply parentheses

9b-(4(b+23))+27=0


We calculate terms in parentheses: -(4(b+23)), so:

4(b+23)

We multiply parentheses

4b+92

Back to the equation:

-(4b+92)


We get rid of parentheses

9b-4b-92+27=0

We add all the numbers together, and all the variables

5b-65=0

We move all terms containing b to the left, all other terms to the right

5b=65

b=65/5

b=13