9(2z-7)=11(z+14)

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Solution for 9(2z-7)=11(z+14) equation: 



9(2z-7)=11(z+14)

We move all terms to the left:

9(2z-7)-(11(z+14))=0

We multiply parentheses

18z-(11(z+14))-63=0



We calculate terms in parentheses: -(11(z+14)), so:

11(z+14)

We multiply parentheses

11z+154

Back to the equation:

-(11z+154)



We get rid of parentheses

18z-11z-154-63=0

We add all the numbers together, and all the variables

7z-217=0

We move all terms containing z to the left, all other terms to the right

7z=217

z=217/7

z=31

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